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(A) For parallel combination of capacitors,the equivalent capacitance is given by $C_p = C_1 + C_2 + C_3 = 4 + 6 + 12 = 22 \mu F$. For series combinat

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$1: 11$

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(A) For parallel combination of capacitors,the equivalent capacitance is given by $C_p = C_1 + C_2 + C_3 = 4 + 6 + 12 = 22 \mu F$. For series combination of capacitors,the equivalent capacitance $C_s$ is given by $\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} = \frac{1}{4} + \frac{1}{6} + \frac{1}{12} = \frac{3+2+1}{12} = \frac{6}{12} = \frac{1}{2} \mu F^{-1}$. Therefore,$C_s = 2 \mu F$. The ratio of effective capacitances in series to parallel is $\frac{C_s}{C_p} = \frac{2}{22} = 1: 11$.

Three parallel plate capacitors of capacitances $4 \mu F$,$6 \mu F$ and $12 \mu F$ are first connected in series and then in parallel. The ratio of the effective capacitances in the two cases is

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