Three substances A,B and C react to form E an | vedclass

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(C) The balanced chemical equation is $2A + 3B + C \rightarrow 4D + 2E$.First,calculate the mass of one stoichiometric unit of the reactants: $2(40) +

Vedclass · Accepted Answer

$390$

Vedclass · Answer

(C) The balanced chemical equation is $2A + 3B + C ightarrow 4D + 2E$.First,calculate the mass of one stoichiometric unit of the reactants: $2(40) + 3(30) + 1(20) = 80 + 90 + 20 = 190 \ g$.Since $570 \ g$ of the mixture is used,the number of stoichiometric units reacting is $570 / 190 = 3$.According to the stoichiometry,$1$ unit of reaction produces $2$ moles of $E$. Therefore,$3$ units produce $3 	imes 2 = 6 \ moles$ of $E$.Using the law of conservation of mass: $Mass_{reactants} = Mass_{products}$.$570 \ g = Mass_{D} + Mass_{E}$.Mass of $D$ produced $= 3 	imes (4 	imes 15) = 3 	imes 60 = 180 \ g$.Mass of $E = 570 \ g - 180 \ g = 390 \ g$.

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