Three successive measurements in an experimen | vedclass

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(C) The average value is calculated as: $	ext{Average} = \frac{10.9 + 11.4042 + 11.42}{3} = \frac{33.7242}{3} = 11.2414$. According to the rules of s

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$11.2$

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(C) The average value is calculated as: $	ext{Average} = \frac{10.9 + 11.4042 + 11.42}{3} = \frac{33.7242}{3} = 11.2414$. According to the rules of significant figures in addition/subtraction,the result should be reported to the same number of decimal places as the measurement with the fewest decimal places. The values are $10.9$ ($1$ decimal place),$11.4042$ ($4$ decimal places),and $11.42$ ($2$ decimal places). The measurement with the fewest decimal places is $10.9$ (which has $1$ decimal place). Therefore,the average value must be rounded to $1$ decimal place,which is $11.2$.

Prefixes	Multiples
$i$. micro	$10^6$
$ii$. deca	$10^9$
$iii$. mega	$10^{-6}$
$iv$. giga	$10^{15}$
$v$. femto	$10$

Three successive measurements in an experiment gave the values $10.9$,$11.4042$,and $11.42$. The correct way of reporting the average value is

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Match the following prefixes with their multiples:

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$iv$. giga $10^{15}$

$v$. femto $10$

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