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(B) The total number of elements is $Z_{\max} = 5$. If electrons have no spin,there is no spin quantum number. For a given principal quantum number $n

Vedclass · Accepted Answer

$n_{\max} = 2$,and electrons are spinless but nevertheless obey the Pauli Exclusion principle.

Vedclass · Answer

(B) The total number of elements is $Z_{\max} = 5$. If electrons have no spin,there is no spin quantum number. For a given principal quantum number $n$,the number of orbitals is $n^2$. If $n_{\max} = 2$,the available orbitals are: $n=1$: $1s$ ($1$ orbital) $n=2$: $2s$ ($1$ orbital) and $2p$ ($3$ orbitals) Total orbitals = $1 + 1 + 3 = 5$. Since the Pauli Exclusion principle is obeyed,each orbital can hold only one electron (as there is no spin quantum number to distinguish states). Thus,with $5$ orbitals,we can accommodate $5$ electrons,which corresponds to $Z_{\max} = 5$. Therefore,$n_{\max} = 2$ and electrons are spinless.

To accommodate the view that matter is made up of $5$ elements only,a scientist proposed the following hypothesis: atoms can have a maximum principal quantum number $n_{\max}$ and no higher. Then,which of the following statements must be true?

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