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(D) $KMnO_4$ is a strong oxidizing agent. It oxidizes reducing agents like $NO_2^-$,$S^{2-}$,and $Cl^-$ (in specific conditions) to their higher oxida

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$CO_3^{2-}$

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(D) $KMnO_4$ is a strong oxidizing agent. It oxidizes reducing agents like $NO_2^-$,$S^{2-}$,and $Cl^-$ (in specific conditions) to their higher oxidation states,resulting in the decolourisation of the purple $KMnO_4$ solution. $CO_3^{2-}$ contains carbon in its maximum oxidation state of $+4$,so it cannot be further oxidized by $KMnO_4$. Therefore,$CO_3^{2-}$ will not decolourise the $KMnO_4$ solution.

To an acidic solution of an anion,a few drops of $KMnO_4$ solution are added. Which of the following,if present,will not decolourise the $KMnO_4$ solution?

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