To construct a triangle similar to a given $\triangle ABC$ with its sides $\frac{3}{7}$ of the corresponding sides of $\triangle ABC$,first draw a ray $BX$ such that $\angle CBX$ is an acute angle and $X$ lies on the opposite side of $A$ with respect to $BC$. Then locate points $B_{1}, B_{2}, B_{3}, \dots$ on $BX$ at equal distances and the next step is to join

  • A
    $B_{10}$ to $C$
  • B
    $B_{7}$ to $C$
  • C
    $B_{13}$ to $C$
  • D
    $B_{4}$ to $C$

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Give the justification of the construction also:
Draw a triangle $ABC$ with side $BC = 7 \, cm$,$\angle B = 45^{\circ}$,$\angle A = 105^{\circ}$. Then,construct a triangle whose sides are $\frac{4}{3}$ times the corresponding sides of $\triangle ABC$.

To construct a triangle similar to a given $\triangle ABC$ with its sides being $\frac{8}{5}$ of the corresponding sides of $\triangle ABC$,a ray $BX$ is drawn such that $\angle CBX$ is an acute angle and $X$ is on the opposite side of $A$ with respect to $BC$. The minimum number of points to be located at equal distances on ray $BX$ is

Draw $\Delta XYZ$ with $XY = 4\, cm$,$YZ = 6\, cm$,and $XZ = 7\, cm$. Then,construct $\Delta YMN$ similar to $\Delta XYZ$ with a scale factor of $\frac{4}{3}$. Write the steps of construction.

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Give the justification of the construction also:
Construct a triangle with sides $5\, cm$,$6\, cm$,and $7\, cm$ and then another triangle whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle.

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Draw $\Delta PQR$ with $m \angle P=60^{\circ}, m \angle Q=45^{\circ}$ and $PQ =6 \text{ cm}$. Then construct $\Delta PBC$ similar to $\Delta PQR$ whose sides have lengths $\frac{5}{3}$ times the lengths of the corresponding sides of $\Delta PQR$.

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