Calculate the number of moles in 90 text{ g} | vedclass

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(B) Given mass of water $= 90 	ext{ g}$.The molar mass of water $(H_2O)$ is calculated as follows:$H_2O = (2 	imes 1) + 16 = 18 	ext{ g/mol}$.We kn

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$5$

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(B) Given mass of water $= 90 	ext{ g}$.The molar mass of water $(H_2O)$ is calculated as follows:$H_2O = (2 	imes 1) + 16 = 18 	ext{ g/mol}$.We know that the number of moles is calculated by the formula:$	ext{Number of moles} = \frac{	ext{Given mass}}{	ext{Molar mass}}$.Substituting the values:$	ext{Number of moles} = \frac{90 	ext{ g}}{18 	ext{ g/mol}} = 5 	ext{ moles}$.Therefore,there are $5 	ext{ moles}$ in $90 	ext{ g}$ of water.

Calculate the number of moles in $90 \text{ g}$ of water. (in $\text{ moles}$)

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