Train A crosses a pole in 25 text{ seconds} a | vedclass

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Question

(A) Let the length of Train $B$ be $x 	ext{ m}$.Then the length of Train $A$ is $\frac{x}{2} 	ext{ m}$.Time taken by Train $A$ = $25 	ext{ seconds}

Vedclass · Accepted Answer

$3:2$

Vedclass · Answer

(A) Let the length of Train $B$ be $x 	ext{ m}$.Then the length of Train $A$ is $\frac{x}{2} 	ext{ m}$.Time taken by Train $A$ = $25 	ext{ seconds}$.Time taken by Train $B$ = $1 	ext{ minute } 15 	ext{ seconds} = 60 + 15 = 75 	ext{ seconds}$.Speed of Train $A$ = $\frac{	ext{Distance}}{	ext{Time}} = \frac{x/2}{25} = \frac{x}{50} 	ext{ m/s}$.Speed of Train $B$ = $\frac{	ext{Distance}}{	ext{Time}} = \frac{x}{75} 	ext{ m/s}$.Ratio of speed of Train $A$ to Train $B$ = $\frac{x/50}{x/75} = \frac{75}{50} = \frac{3}{2} = 3:2$.

Train $A$ crosses a pole in $25 \text{ seconds}$ and another Train $B$ crosses a pole in $1 \text{ minute}$ and $15 \text{ seconds}$. The length of Train $A$ is half the length of Train $B$. What is the respective ratio between the speeds of Train $A$ and Train $B$?

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