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(B) Let the resistance of each resistor be $R = 10\,\Omega$.In series connection,the equivalent resistance is $R_s = R + R = 2R = 2 	imes 10 = 20\,\O

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$4:1$

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(B) Let the resistance of each resistor be $R = 10\,\Omega$.In series connection,the equivalent resistance is $R_s = R + R = 2R = 2 	imes 10 = 20\,\Omega$.In parallel connection,the equivalent resistance $R_p$ is given by $\frac{1}{R_p} = \frac{1}{R} + \frac{1}{R} = \frac{2}{R}$,so $R_p = \frac{R}{2} = \frac{10}{2} = 5\,\Omega$.The ratio of equivalent resistance in series to parallel is $\frac{R_s}{R_p} = \frac{2R}{R/2} = 4:1$.

Two $10\,\Omega$ resistors are first connected in series and then in parallel. What is the ratio of the equivalent resistance in both cases?

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