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(D) In this scenario, we have three mirrors arranged mutually perpendicular to each other (two walls and the ceiling). Let the position of the observe

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$8$

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(D) In this scenario, we have three mirrors arranged mutually perpendicular to each other (two walls and the ceiling). Let the position of the observer be $(x, y, z)$. The images are formed by reflections in the $XY$, $YZ$, and $ZX$ planes. The total number of images formed by three mutually perpendicular mirrors is given by the formula $N = 2^n - 1$, where $n$ is the number of mirrors. Here, $n = 3$, so $N = 2^3 - 1 = 8 - 1 = 7$. However, the observer is inside the room, and one of these images is the observer's own position or is obscured by the observer's body. Specifically, for three mutually perpendicular mirrors, the images are located at $(\pm x, \pm y, \pm z)$ excluding the original position $(x, y, z)$. There are $2^3 = 8$ total positions including the object. Subtracting the object itself, we get $8 - 1 = 7$ images. Since the observer is part of the system, they see $7$ images of themselves.

Two adjacent walls and the ceiling of a rectangular room are mirror surfaced. The number of images of himself that an observer sees is

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