Two balls A and B having masses 1, kg and 2, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Using the Law of Conservation of Linear Momentum:$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$Taking the direction of $A$ as positive: $1(21) + 2(-4) =

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) Using the Law of Conservation of Linear Momentum:$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$Taking the direction of $A$ as positive: $1(21) + 2(-4) = 1(1) + 2 v_2$$21 - 8 = 1 + 2 v_2 \Rightarrow 13 = 1 + 2 v_2 \Rightarrow 2 v_2 = 12 \Rightarrow v_2 = 6\, m/s$.Since $v_2$ is positive,$B$ moves in the original direction of $A$,which is opposite to its initial direction.Coefficient of Restitution $(e)$:$e = \frac{v_2 - v_1}{u_1 - u_2} = \frac{6 - 1}{21 - (-4)} = \frac{5}{25} = 0.2$.Loss of Kinetic Energy $(\Delta K)$:$\Delta K = K_i - K_f = [\frac{1}{2} m_1 u_1^2 + \frac{1}{2} m_2 u_2^2] - [\frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2]$$K_i = \frac{1}{2}(1)(21^2) + \frac{1}{2}(2)(4^2) = 220.5 + 16 = 236.5\, J$.$K_f = \frac{1}{2}(1)(1^2) + \frac{1}{2}(2)(6^2) = 0.5 + 36 = 36.5\, J$.$\Delta K = 236.5 - 36.5 = 200\, J$.

Two balls $A$ and $B$ having masses $1\, kg$ and $2\, kg$,moving with speeds $21\, m/s$ and $4\, m/s$ respectively in opposite directions,collide head-on. After the collision,$A$ moves with a speed of $1\, m/s$ in the same direction. Which of the following statements is correct?

Similar Questions

$A$ wooden block of mass $M$ is suspended by a cord and is at rest. $A$ bullet of mass $m$,moving with a velocity $v$,passes through the block and emerges with a velocity $v/2$ in the same direction. If the block rises to a height $H$,calculate the value of $H$.

$A$ ball is falling freely from a height. When it reaches $10 ~m$ height from the ground, its velocity is $v_0$. It collides with the ground, loses $50 \%$ of its energy, and rises back to a height of $10 ~m$. Then the velocity $v_0$ is (in $~m / s$)

Which of the following graphs correctly represents the relationship between kinetic energy $(E)$,potential energy $(U)$,and height $(h)$ from the ground for a particle moving vertically?

$A$ ball is allowed to fall from a height of $10 \, m$. If there is $40 \%$ loss of energy due to impact,then after one impact the ball will rise to a height of ........ $m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module