Two bodies $A$ and $B$ of masses $20 \ kg$ and $5 \ kg$ respectively are at rest. Due to the action of a force of $40 \ N$ separately,if the two bodies acquire equal kinetic energies in times $t_A$ and $t_B$ respectively,then $t_A: t_B=$

  • A
    $1: 2$
  • B
    $2: 1$
  • C
    $2: 5$
  • D
    $5: 6$

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