Two capacitors of 10 pF and 20 pF are conne | vedclass

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(A) The common potential $V$ of two capacitors connected in parallel is given by the formula: $V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2}$.Given: $C_1 =

Vedclass · Accepted Answer

$133.3$

Vedclass · Answer

(A) The common potential $V$ of two capacitors connected in parallel is given by the formula: $V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2}$.Given: $C_1 = 10 \ pF$,$V_1 = 200 \ V$,$C_2 = 20 \ pF$,$V_2 = 100 \ V$.Substituting the values:$V = \frac{(10 	imes 10^{-12} 	imes 200) + (20 	imes 10^{-12} 	imes 100)}{10 	imes 10^{-12} + 20 	imes 10^{-12}}$$V = \frac{2000 	imes 10^{-12} + 2000 	imes 10^{-12}}{30 	imes 10^{-12}}$$V = \frac{4000 	imes 10^{-12}}{30 	imes 10^{-12}} = \frac{400}{3} \approx 133.33 \ V$.Thus,the common potential is $133.33 \ V$.

Two capacitors of $10 \ pF$ and $20 \ pF$ are connected to $200 \ V$ and $100 \ V$ sources respectively. If they are connected by a wire,what is the common potential of the capacitors (in $V$)?

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