Two capacitors of capacities C_1 and C_2 are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When two capacitors are connected in parallel,charge flows from the capacitor at a higher potential to the one at a lower potential until both rea

Vedclass · Accepted Answer

$V_1 = V_2$

Vedclass · Answer

(C) When two capacitors are connected in parallel,charge flows from the capacitor at a higher potential to the one at a lower potential until both reach a common potential.Energy loss occurs during this redistribution of charge.The loss in energy is given by the formula: $\Delta U = \frac{C_1 C_2}{2(C_1 + C_2)} (V_1 - V_2)^2$.For there to be no exchange or loss of energy,$\Delta U$ must be $0$.This implies $(V_1 - V_2)^2 = 0$,which means $V_1 = V_2$.Therefore,if the initial voltages are equal,there is no charge flow and no energy loss.

Two capacitors of capacities $C_1$ and $C_2$ are charged to voltages $V_1$ and $V_2$ respectively. There will be no exchange of energy in connecting them in parallel,if

Similar Questions

Find the heat produced in the capacitors on closing the switch $S$. (in $J$)

Initially $n$ identical capacitors are joined in parallel and are charged to potential $V$. Now they are separated and joined in series. Then

What are the charges stored in the $1 \,\mu F$ and $2 \,\mu F$ capacitors in the circuit below,once the currents become steady?

Two capacitors are shown in the diagram. Each is charged to potential $V_0$. If capacitor $C$ is filled with a dielectric of constant $2$ and capacitor $2C$ is filled with a dielectric of constant $3$,then the key is closed. The final voltage on the capacitor $C$ will be:

Three capacitors each having capacitance $C = 2\,\mu F$ are connected with a battery of $e.m.f.$ $30\, V$ as shown in the figure. When the switch $S$ is closed,then select the incorrect statement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module