Two capillary tubes of same diameter are kept vertically in two liquids whose densities are in the ratio $4:3$. If their surface tensions are in the ratio $6:5$,the ratio of heights $\left(\frac{h_1}{h_2}\right)$ of liquids in the two capillary tubes is (Their angle of contacts are same).

In the state of weightlessness,a capillary tube is dipped in water,then water

$A$ capillary tube of radius '$r$' is immersed in water and water rises to a height of '$h$'. The mass of water in the capillary tube is $5 \times 10^{-3} \ kg$. The same capillary tube is now immersed in a liquid whose surface tension is $\sqrt{2}$ times the surface tension of water. The angle of contact between the capillary tube and this liquid is $45^{\circ}$. The mass of liquid which rises into the capillary tube now is (in $kg$):

Water rises to a height $h$ in a capillary tube. If the length of the capillary tube above the surface of water is made less than $h,$ then

If a capillary tube is tilted to $45^o$ and $60^o$ from the vertical,then the ratio of the lengths $l_1$ and $l_2$ of the liquid columns in it will be:

$A$ vertical glass capillary tube open at both ends contains some water. Which of the following shapes may be taken by the water in the tube?