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(C) standard pack of cards contains $52$ cards,out of which $4$ are kings.When the first card is drawn,the probability of it being a king is $P(K_1) =

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$\frac{1}{221}$

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(C) standard pack of cards contains $52$ cards,out of which $4$ are kings.When the first card is drawn,the probability of it being a king is $P(K_1) = \frac{4}{52} = \frac{1}{13}$.After drawing one king,there are $51$ cards remaining in the pack,and only $3$ kings left.Therefore,the probability of the second card being a king,given that the first was a king,is $P(K_2 | K_1) = \frac{3}{51} = \frac{1}{17}$.The probability that both cards are kings is $P(K_1 \cap K_2) = P(K_1) 	imes P(K_2 | K_1) = \frac{4}{52} 	imes \frac{3}{51} = \frac{1}{13} 	imes \frac{1}{17} = \frac{1}{221}$.

Two cards are drawn one by one at random from a pack of $52$ cards. The probability that both of them are kings is:

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