Two cars A and B each of mass 10^3 text{ kg} | vedclass

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(B) The angular momentum of a particle relative to another particle is given by $L = m \cdot v_{	ext{rel}} \cdot r_{\perp}$.Here, the mass of car $A$

Vedclass · Accepted Answer

$10^5$

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(B) The angular momentum of a particle relative to another particle is given by $L = m \cdot v_{	ext{rel}} \cdot r_{\perp}$.Here, the mass of car $A$ is $m = 10^3 	ext{ kg}$.The relative velocity of car $A$ with respect to car $B$ is $v_{	ext{rel}} = v_A - v_B = 72 	ext{ km/h} - 36 	ext{ km/h} = 36 	ext{ km/h}$.Converting the relative velocity to $SI$ units: $v_{	ext{rel}} = 36 	imes \frac{5}{18} 	ext{ m/s} = 10 	ext{ m/s}$.The perpendicular distance between the tracks is $r_{\perp} = 10 	ext{ m}$.Substituting these values into the formula: $L = 1000 	imes 10 	imes 10 = 10^5 	ext{ kg} \cdot 	ext{m}^2/	ext{s}$ (or $	ext{J} \cdot 	ext{s}$).

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