Two cities are $150\, km$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $km$ is $8\, V$ and the average resistance per $km$ is $0.5\, \Omega$. The power loss in the wire is
- A$19.2\, W$
- B$19.2\, kW$
- C$12.2\, kW$
- D$12.2\, W$
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Resistors of $1\, \Omega$, $2\, \Omega$, and $3\, \Omega$ are connected in the form of a triangle. If a $1.5\, V$ cell of negligible internal resistance is connected across the $3\, \Omega$ resistor, the current flowing through this resistance will be ................ $A$.
Medium
View SolutionIn the given circuit,the internal resistance of the $18\,V$ cell is negligible. If $R_1 = 400\,\Omega$,$R_3 = 100\,\Omega$,and $R_4 = 500\,\Omega$,and the reading of an ideal voltmeter across $R_4$ is $5\,V$,then the value of $R_2$ will be ........... $\Omega$.
In the given circuit,the current in each resistance is: (in $A$)
$A$ battery of $e.m.f.$ $10\, V$ is connected to a resistance network as shown in the figure. The potential difference ${V_A} - {V_B}$ between the points $A$ and $B$ is .................... $V$.
Difficult
View SolutionFor the circuits $A$ and $B$ as shown in the figure,identify the correct option.
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