Two closed organ pipes of length 100,cm and 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The fundamental frequency of a closed organ pipe is given by $f = \frac{v}{4L}$,where $v$ is the velocity of sound and $L$ is the length of the pi

Vedclass · Accepted Answer

$323.2$

Vedclass · Answer

(C) The fundamental frequency of a closed organ pipe is given by $f = \frac{v}{4L}$,where $v$ is the velocity of sound and $L$ is the length of the pipe.The beat frequency is the difference between the fundamental frequencies of the two pipes: $f_{beat} = |f_1 - f_2| = \frac{16}{20} = 0.8\,Hz$.Given $L_1 = 100\,cm = 1\,m$ and $L_2 = 101\,cm = 1.01\,m$,we have:$f_1 = \frac{v}{4 	imes 1}$ and $f_2 = \frac{v}{4 	imes 1.01}$.$f_1 - f_2 = \frac{v}{4} \left( \frac{1}{1} - \frac{1}{1.01} ight) = 0.8$.$\frac{v}{4} \left( \frac{1.01 - 1}{1.01} ight) = 0.8$.$\frac{v}{4} \left( \frac{0.01}{1.01} ight) = 0.8$.$v = \frac{0.8 	imes 4 	imes 1.01}{0.01} = 80 	imes 4.04 = 323.2\,m/s$.

Two closed organ pipes of length $100\,cm$ and $101\,cm$ long give $16$ beats in $20\,sec$ when each pipe is sounded in fundamental mode. Calculate the velocity of sound in $m/s$.

Similar Questions

Which of the following properties does not support the anomalous behavior of boron?

The major product of the following reaction is

Which photosynthetic pigments are present in algae?

If $(2, -1, 3)$ is the foot of the perpendicular drawn from the origin to a plane, then the equation of that plane is

Vedclass Test Series

Exam Paper Generator

Online Exam Module