Two coils of wire A and B are placed mutually | vedclass

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(C) The magnetic field lines produced by a circular coil are perpendicular to the plane of the coil at its center. Since the two coils $A$ and $B$ are

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no current will be induced in another coil.

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(C) The magnetic field lines produced by a circular coil are perpendicular to the plane of the coil at its center. Since the two coils $A$ and $B$ are placed mutually perpendicular,the magnetic field lines produced by coil $A$ will lie in the plane of coil $B$,and vice-versa. The magnetic flux $\Phi$ is given by $\Phi = \vec{B} \cdot \vec{A} = BA \cos 	heta$,where $	heta$ is the angle between the magnetic field vector $\vec{B}$ and the area vector $\vec{A}$ (which is perpendicular to the plane of the coil). Since the magnetic field lines are parallel to the plane of the other coil,they are perpendicular to the area vector of that coil. Thus,$	heta = 90^\circ$ and $\cos 90^\circ = 0$. Therefore,the magnetic flux linked with the other coil is zero. According to Faraday's law of electromagnetic induction,the induced $EMF$ is $\varepsilon = -d\Phi/dt$. Since $\Phi = 0$ at all times,the induced $EMF$ and consequently the induced current will be zero.

Two coils of wire $A$ and $B$ are placed mutually perpendicular as shown in the figure. When the current is changed in any one coil:

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