Two damped spring-mass oscillating systems have identical spring constants and decay times. However,system $A$'s mass $m_A$ is twice system $B$'s mass $m_B$. How do their damping constants,$b$,compare?

In forced oscillations,a particle oscillates simple harmonically with a frequency equal to

The displacement of a damped harmonic oscillator is given by $x(t) = e^{-0.1 t} \cos(10 \pi t + \varphi)$. Here $t$ is in seconds. The time taken for its amplitude of vibration to drop to half of its initial value is close to: (in $s$)

Write the expression for the mechanical energy of a damped oscillator.

$A$ spring-mass system executes damped harmonic oscillations given by the equation $y = A e^{-\frac{bt}{2m}} \sin(\omega' t + \phi)$,where the symbols have their usual meanings. If a $2 \ kg$ mass $(m)$ is attached to a spring of force constant $(K) = 1250 \ N/m$,the period of the oscillation is $(\pi / 12) \ s$. The damping constant $b$ has the value ..... $kg/s$.

Sometimes when the speed of a vehicle is increased,its body starts to bounce. Why?