Two ideal diodes are connected in the network | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a potential difference is applied between $A$ and $B$ such that $A$ is at a higher potential $(+)$ and $B$ is at a lower potential $(-)$, the

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(B) When a potential difference is applied between $A$ and $B$ such that $A$ is at a higher potential $(+)$ and $B$ is at a lower potential $(-)$, the left diode becomes forward-biased and acts as a short circuit (zero resistance), while the right diode becomes reverse-biased and acts as an open circuit (infinite resistance).In this state, the circuit simplifies to two parallel branches connected in series with the rest of the network. Specifically, the $20\,\Omega$ resistor (top) and the $20\,\Omega$ resistor (bottom) are in parallel. Their equivalent resistance is $R_p = \frac{20 	imes 20}{20 + 20} = 10\,\Omega$.This $10\,\Omega$ equivalent resistance is in series with the $15\,\Omega$ resistor.Therefore, the total equivalent resistance $R_{eq} = 10\,\Omega + 15\,\Omega = 25\,\Omega$.

Two ideal diodes are connected in the network as shown in the figure. The equivalent resistance between $A$ and $B$ is $.......\Omega$.

Similar Questions

Find the magnitude of current in the given circuit. (in $A$)

When a reverse bias is applied to a $p-n$ junction diode,what happens to the potential barrier?

Which one of the diodes given below is reverse biased?

$A$ $2 \ V$ cell is connected across points $A$ and $B$ as shown in the figure. Assume that the resistance of each diode is zero in forward bias and infinity in reverse bias. The current supplied by the cell is (in $A$)

$A$ crystal diode is a:

Vedclass Test Series

Exam Paper Generator

Online Exam Module