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(D) In the given circuit,the positive terminal of the battery is connected to the p-side of diode $D_{1}$ and the n-side of diode $D_{2}$.Diode $D_{1}

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$0.5$

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(D) In the given circuit,the positive terminal of the battery is connected to the p-side of diode $D_{1}$ and the n-side of diode $D_{2}$.Diode $D_{1}$ is in forward bias,so it acts as a closed switch (zero resistance).Diode $D_{2}$ is in reverse bias,so it acts as an open switch (infinite resistance).Therefore,the current flows only through the branch containing $D_{1}$ and the $10 \ \Omega$ resistor.The current $I$ supplied by the battery is given by Ohm's law:$I = \frac{V}{R} = \frac{5 \ V}{10 \ \Omega} = 0.5 \ A$.

Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is......$A$

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