Two identical charged spherical drops, each o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the radius of each small drop be $r$. The capacitance of a spherical drop is given by $C = 4\pi\epsilon_0 r$.When two identical drops of radiu

Vedclass · Accepted Answer

less than $2C$ but greater than $C$

Vedclass · Answer

(C) Let the radius of each small drop be $r$. The capacitance of a spherical drop is given by $C = 4\pi\epsilon_0 r$.When two identical drops of radius $r$ merge to form a larger drop of radius $R$, the volume remains conserved.So, $\frac{4}{3}\pi R^3 = 2 	imes \frac{4}{3}\pi r^3$, which gives $R = 2^{1/3}r$.The capacitance of the new large drop is $C' = 4\pi\epsilon_0 R$.Substituting $R = 2^{1/3}r$, we get $C' = 4\pi\epsilon_0 (2^{1/3}r) = 2^{1/3}C$.Since $1 < 2^{1/3} < 2$, the resultant capacitance $C'$ is less than $2C$ but greater than $C$.

Two identical charged spherical drops, each of capacitance $C$, merge to form a single drop. The resultant capacitance is:

Similar Questions

Find the oxidation state of sodium in $Na_{2}O_{2}$.

$x=\cos ^{-1}\left(\frac{1}{\sqrt{1+t^2}}\right), y=\sin ^{-1}\left(\frac{t}{\sqrt{1+t^2}}\right) \Rightarrow \frac{d y}{d x}$ is equal to

Which among the following has the highest melting point?

Which of the following is not an isotope of hydrogen?

The solution of the differential equation $\frac{dy}{dx} = \frac{x - y + 3}{2(x - y) + 5}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module