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(C) Let the two identical charges be $q$ at positions $0$ and $d$ on the $x$-axis.At a point $P$ at distance $x$ from the first charge, the electric f

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(C) Let the two identical charges be $q$ at positions $0$ and $d$ on the $x$-axis.At a point $P$ at distance $x$ from the first charge, the electric field $E$ is given by:$E = \frac{kq}{x^2} - \frac{kq}{(d-x)^2}$At the midpoint $x = d/2$, $E = \frac{kq}{(d/2)^2} - \frac{kq}{(d/2)^2} = 0$.For $x For $x > d/2$, the second term is greater, so $E$ is negative.As $x 	o 0$, $E 	o \infty$. As $x 	o d$, $E 	o -\infty$.The curve that shows a positive value decreasing to zero at $x = d/2$ and then becoming negative and decreasing further is represented by the graph in option $C$.

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