Two men undertake a piece of work for Rs. 600 | vedclass

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(C) The first man's $3$ days' work $= \frac{3}{6} = \frac{1}{2}$.The second man's $3$ days' work $= \frac{3}{8}$.The boy's $3$ days' work $= 1 - (\fra

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$75$

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(C) The first man's $3$ days' work $= \frac{3}{6} = \frac{1}{2}$.The second man's $3$ days' work $= \frac{3}{8}$.The boy's $3$ days' work $= 1 - (\frac{1}{2} + \frac{3}{8}) = 1 - (\frac{4+3}{8}) = 1 - \frac{7}{8} = \frac{1}{8}$.Since the total work is completed in $3$ days,the ratio of work done by the first man,the second man,and the boy is $\frac{1}{2} : \frac{3}{8} : \frac{1}{8}$.Multiplying by $8$,the ratio becomes $4 : 3 : 1$.The boy's share $= \frac{1}{4+3+1} 	imes 600 = \frac{1}{8} 	imes 600 = Rs. 75$.

Two men undertake a piece of work for $Rs. 600$. Individually,they can complete the work in $6$ days and $8$ days,respectively. With the assistance of a boy,they completed the work in $3$ days. The boy's share should be (in $Rs.$)

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