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(C) The number of images $n$ formed by two plane mirrors inclined at an angle $	heta$ is given by $n = \frac{360^{\circ}}{	heta} - 1$ if $\frac{360^

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$11$

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(C) The number of images $n$ formed by two plane mirrors inclined at an angle $	heta$ is given by $n = \frac{360^{\circ}}{	heta} - 1$ if $\frac{360^{\circ}}{	heta}$ is an even integer, or if it is an odd integer and the object is placed symmetrically.Given $n = 5$, we have $5 = \frac{360^{\circ}}{	heta} - 1$, which implies $\frac{360^{\circ}}{	heta} = 6$.Thus, $	heta = \frac{360^{\circ}}{6} = 60^{\circ}$.When the angle is decreased by $30^{\circ}$, the new angle $	heta' = 60^{\circ} - 30^{\circ} = 30^{\circ}$.The new number of images $n'$ is given by $n' = \frac{360^{\circ}}{30^{\circ}} - 1 = 12 - 1 = 11$.

Two mirrors at an angle $\theta^{\circ}$ produce $5$ images of a point. The number of images produced when $\theta$ is decreased to $\theta^{\circ}-30^{\circ}$ is

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