Two moles of an ideal monoatomic gas undergo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: $n = 2 	ext{ moles}$,$T_3 = 2400 	ext{ K}$,$2 T_4 = 2400 \implies T_4 = 1200 	ext{ K}$,$3 T_2 = 2400 \implies T_2 = 800 	ext{ K}$,$6 T_

Vedclass · Accepted Answer

$1600$

Vedclass · Answer

(B) Given: $n = 2 	ext{ moles}$,$T_3 = 2400 	ext{ K}$,$2 T_4 = 2400 \implies T_4 = 1200 	ext{ K}$,$3 T_2 = 2400 \implies T_2 = 800 	ext{ K}$,$6 T_1 = 2400 \implies T_1 = 400 	ext{ K}$.From the graph,the process $1 	o 2$ is isochoric $(P = 	ext{constant})$,$2 	o 3$ is isobaric $(P \propto T)$,$3 	o 4$ is isochoric,and $4 	o 1$ is isobaric.Work done in a cycle $W = \oint P \, dV$. Using $PV = nRT$,$W = \oint nR \, dT$ for isobaric processes.$W_{12} = 0$ (isochoric).$W_{23} = nR(T_3 - T_2) = 2R(2400 - 800) = 3200R$.$W_{34} = 0$ (isochoric).$W_{41} = nR(T_1 - T_4) = 2R(400 - 1200) = -1600R$.Total work $W = W_{12} + W_{23} + W_{34} + W_{41} = 0 + 3200R + 0 - 1600R = 1600R$.

Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. The temperatures in different states are given as $6 T_1 = 3 T_2 = 2 T_4 = T_3 = 2400 \text{ K}$. The work done by the gas during the complete cycle is $(R = \text{Universal gas constant})$ (in $R$)

Similar Questions

According to the $PV$ diagram shown in the figure,a thermodynamic system is taken from state $A$ to state $B$ along the path $ACB$ and is brought back to state $A$ along the path $BDA$. The net work done during the complete cycle is given by the area of:

$A$ thermodynamic system undergoes a cyclic process $ABC$ as shown in the diagram. The work done by the system per cycle is (in $J$)

An ideal gas undergoes a cyclic process as shown in the diagram. The net work done by the gas in the cycle is

In the given figure,two processes $A$ and $B$ are shown by which a thermodynamic system goes from an initial state $i$ to a final state $f$. If $\Delta Q_A$ and $\Delta Q_B$ are respectively the heats supplied to the systems,then:

One mole of an ideal gas is taken from $A$ to $B$,from $B$ to $C$,and then back to $A$. The variation of its volume with temperature for that change is as shown. Its pressure at $A$ is $P_{0}$ and volume is $V_{0}$. Then,the internal energy:

Vedclass Test Series

Exam Paper Generator

Online Exam Module