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(C) The resultant intensity $I$ of two interfering waves with amplitudes $A_1$ and $A_2$ and phase difference $\phi$ is given by the formula:$I = A_1^

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$7$

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(C) The resultant intensity $I$ of two interfering waves with amplitudes $A_1$ and $A_2$ and phase difference $\phi$ is given by the formula:$I = A_1^2 + A_2^2 + 2A_1A_2 \cos \phi$Given the amplitudes $A_1 = A$ and $A_2 = 2A$,and the phase difference $\phi = 60^{\circ}$:$I = A^2 + (2A)^2 + 2(A)(2A) \cos 60^{\circ}$Substitute $\cos 60^{\circ} = 0.5$:$I = A^2 + 4A^2 + 4A^2(0.5)$$I = 5A^2 + 2A^2$$I = 7A^2$Thus,the intensity at that point is proportional to $7A^2$.

Two monochromatic coherent light waves of amplitudes $A$ and $2A$,interfering at a point,have a phase difference of $60^{\circ}$. The intensity at that point will be proportional to (in $A^2$)

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