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(A) The force per unit length $f$ between two parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $d$ is given by the formula:$f

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$6 	imes 10^{-7} 	ext{ N m}^{-1}$ repulsive

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(A) The force per unit length $f$ between two parallel wires carrying currents $I_1$ and $I_2$ separated by a distance $d$ is given by the formula:$f = \frac{\mu_0}{4\pi} \frac{2 I_1 I_2}{d}$Given values are $I_1 = 1 	ext{ A}$,$I_2 = 3 	ext{ A}$,$d = 1 	ext{ m}$,and $\frac{\mu_0}{4\pi} = 10^{-7} 	ext{ T m A}^{-1}$.Substituting these values into the formula:$f = 10^{-7} 	imes \frac{2 	imes 1 	imes 3}{1} = 6 	imes 10^{-7} 	ext{ N m}^{-1}$Since the currents flow in opposite directions,the force between the wires is repulsive.Therefore,the force per unit length is $6 	imes 10^{-7} 	ext{ N m}^{-1}$ and it is repulsive.

Two parallel wires $1 \text{ m}$ apart carry currents of $1 \text{ A}$ and $3 \text{ A}$ respectively in opposite directions. The force per unit length acting between these two wires is

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