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(C) Let the point where the gravitational field intensity is zero be at a distance $r$ from the mass $m$. Then the distance of this point from the mas

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$\frac{d}{1+\sqrt{2}}$ from point mass $m$

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(C) Let the point where the gravitational field intensity is zero be at a distance $r$ from the mass $m$. Then the distance of this point from the mass $2m$ is $(d-r)$.At this point,the gravitational field intensity due to both masses must be equal in magnitude and opposite in direction.$\frac{Gm}{r^2} = \frac{G(2m)}{(d-r)^2}$$\frac{1}{r^2} = \frac{2}{(d-r)^2}$Taking the square root on both sides:$\frac{1}{r} = \frac{\sqrt{2}}{d-r}$$d-r = \sqrt{2}r$$d = r(1+\sqrt{2})$$r = \frac{d}{1+\sqrt{2}}$Thus,the point is at a distance $\frac{d}{1+\sqrt{2}}$ from the point mass $m$.

Two point masses having mass $m$ and $2m$ are placed at a distance $d$. The point on the line joining the point masses,where the gravitational field intensity is zero,will be at a distance ............

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