Two points (a, 0) and (0, b) are joined by a | vedclass

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Question

(A) The equation of the line passing through the points $(a, 0)$ and $(0, b)$ is given by the intercept form: $\frac{x}{a} + \frac{y}{b} = 1$.To check

Vedclass · Accepted Answer

$(3a, -2b)$

Vedclass · Answer

(A) The equation of the line passing through the points $(a, 0)$ and $(0, b)$ is given by the intercept form: $\frac{x}{a} + \frac{y}{b} = 1$.To check which point lies on the line,we substitute the coordinates $(x, y)$ of each option into the equation.For option $A$: $(3a, -2b)$,we have $\frac{3a}{a} + \frac{-2b}{b} = 3 - 2 = 1$.Since the equation is satisfied,the point $(3a, -2b)$ lies on the line.

Two points $(a, 0)$ and $(0, b)$ are joined by a straight line. Another point on this line is:

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