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(D) The distance of the $n^{th}$ bright fringe from the centre is given by the formula: $x_n = \frac{n \lambda D}{d}$ Given: $n = 3$ $\lambda = 6000\

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$9$

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(D) The distance of the $n^{th}$ bright fringe from the centre is given by the formula: $x_n = \frac{n \lambda D}{d}$ Given: $n = 3$ $\lambda = 6000\ \mathring A = 6000 	imes 10^{-10}\ m = 6 	imes 10^{-7}\ m$ $D = 2.5\ m$ $d = 0.5\ mm = 0.5 	imes 10^{-3}\ m$ Substituting the values: $x_3 = \frac{3 	imes (6 	imes 10^{-7}) 	imes 2.5}{0.5 	imes 10^{-3}}$ $x_3 = \frac{45 	imes 10^{-7}}{0.5 	imes 10^{-3}} = 90 	imes 10^{-4}\ m = 9 	imes 10^{-3}\ m$ Since $10^{-3}\ m = 1\ mm$,we get: $x_3 = 9\ mm$.

Two slits are separated by a distance of $0.5\, mm$ and illuminated with light of $\lambda = 6000\ \mathring A$. If the screen is placed $2.5\, m$ from the slits,the distance of the third bright fringe from the centre will be........$mm$.

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