Two thin conducting concentric shells of radi | vedclass

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(B) Let the charge on the inner shell after the switch is closed be $q$. Since the inner shell is connected to the ground,its potential becomes zero.T

Vedclass · Accepted Answer

$(a)$ is correct,$(b)$ is wrong

Vedclass · Answer

(B) Let the charge on the inner shell after the switch is closed be $q$. Since the inner shell is connected to the ground,its potential becomes zero.The potential at the inner shell of radius $R$ due to its own charge $q$ and the charge $Q$ on the outer shell of radius $2R$ is:$V_{	ext{inner}} = \frac{Kq}{R} + \frac{KQ}{2R} = 0$Solving for $q$:$\frac{Kq}{R} = -\frac{KQ}{2R}$$q = -\frac{Q}{2}$Thus,the potential of the inner shell becomes zero,making statement $(a)$ correct.The charge on the inner shell is $-\frac{Q}{2}$,making statement $(b)$ wrong.Therefore,$(a)$ is correct and $(b)$ is wrong.

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