Two towers A and B,each of height 20 m,are s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The time $t$ taken by both bodies to reach the ground is the same because the initial vertical velocity is zero and the height $h$ of both towers

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The time $t$ taken by both bodies to reach the ground is the same because the initial vertical velocity is zero and the height $h$ of both towers is the same.Using the equation $h = \frac{1}{2}gt^2$,we get $t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 	imes 20}{10}} = 2 \ s$.The horizontal distance covered by the body from tower $A$ is $AP = u_A 	imes t = 20 \ ms^{-1} 	imes 2 \ s = 40 \ m$.The horizontal distance covered by the body from tower $B$ is $QB = u_B 	imes t = 30 \ ms^{-1} 	imes 2 \ s = 60 \ m$.The distance between $P$ and $Q$ is $PQ = 200 \ m - (AP + QB) = 200 \ m - (40 \ m + 60 \ m) = 100 \ m$.For the car,initial velocity $u = 0$,distance $s = 100 \ m$,and time $t = 10 \ s$.Using the equation $s = ut + \frac{1}{2}at^2$,we have $100 = 0 + \frac{1}{2} 	imes a 	imes (10)^2$.$100 = 50a$,which gives $a = 2 \ ms^{-2}$.

Similar Questions

Two wires $A$ and $B$ are of lengths $40 \ cm$ and $30 \ cm$. $A$ is bent into a circle of radius $r$ and $B$ into an arc of radius $r$. $A$ current $i_1$ is passed through $A$ and $i_2$ through $B$. To have the same magnetic inductions at the centre,the ratio of $i_1: i_2$ is

For a reaction $\frac{1}{2} A \rightarrow 2B,$ the rate of disappearance of $A$ is related to the rate of appearance of $B$ by the expression:

The average marks of $10$ students in a class was $60$ with a standard deviation of $4$,while the average marks of another $10$ students was $40$ with a standard deviation of $6$. If all the $20$ students are taken together,their standard deviation will be:

Which one of the following statements is wrong?

The magnetic field $(B)$ inside a long solenoid having $n$ turns per unit length and carrying current $I$ when an iron core is kept in it is ($\mu_0 = $ permeability of vacuum,$\chi = $ magnetic susceptibility).

Vedclass Test Series

Exam Paper Generator

Online Exam Module