Two vectors A and B are inclined at an angle | vedclass

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(A) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$.S

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magnitude

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(A) The magnitude of the resultant $R$ of two vectors $A$ and $B$ inclined at an angle $	heta$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$.Since the magnitudes of $A$ and $B$ and the angle $	heta$ between them remain unchanged when their directions are interchanged,the magnitude of the resultant $R$ remains the same.However,the direction of the resultant vector is given by $	an \phi = \frac{B \sin 	heta}{A + B \cos 	heta}$.When $A$ and $B$ are interchanged,the new angle $\phi'$ becomes $	an \phi' = \frac{A \sin 	heta}{B + A \cos 	heta}$.Since $\phi 
eq \phi'$,the direction of the resultant changes.Therefore,only the magnitude remains the same.

Two vectors $A$ and $B$ are inclined at an angle $\theta$. Their resultant $R$ makes an angle $\phi$ with vector $A$. If the directions of $A$ and $B$ are interchanged,the resultant will have the same:

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