Two vessels contain milk and water in the rat | vedclass

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(B) In the first vessel,the fraction of milk is $\frac{3}{5}$.In the second vessel,the fraction of milk is $\frac{7}{10}$.In the final mixture,the fra

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(B) In the first vessel,the fraction of milk is $\frac{3}{5}$.In the second vessel,the fraction of milk is $\frac{7}{10}$.In the final mixture,the fraction of milk is $\frac{2}{3}$.Using the rule of alligation:Difference $1$ (between second vessel and mixture) $= \frac{7}{10} - \frac{2}{3} = \frac{21-20}{30} = \frac{1}{30}$.Difference $2$ (between mixture and first vessel) $= \frac{2}{3} - \frac{3}{5} = \frac{10-9}{15} = \frac{1}{15}$.The required ratio is the ratio of these differences: $\frac{1}{30} : \frac{1}{15}$.Multiplying both sides by $30$,we get $1 : 2$.

Two vessels contain milk and water in the ratio $3:2$ and $7:3$. Find the ratio in which the contents of the two vessels have to be mixed to get a new mixture in which the ratio of milk and water is $2:1$.

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