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(A, D) Since both wires are made of the same material, their Young's modulus $(Y)$ is identical.Young's modulus is given by $Y = \frac{F L}{A x}$, whe

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Young's modulus of both $A$ and $B$ are the same.

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(A, D) Since both wires are made of the same material, their Young's modulus $(Y)$ is identical.Young's modulus is given by $Y = \frac{F L}{A x}$, where $F$ is the load, $L$ is the length, $A$ is the cross-sectional area, and $x$ is the elongation.Rearranging for the load, we get $F = (\frac{Y A}{L}) x$.Since $Y$ and $L$ are the same for both wires, the slope of the $F-x$ graph is proportional to the cross-sectional area $A$ (i.e.,$	ext{slope} = \frac{Y A}{L} \propto A$).From the graph, the slope of line $A$ is greater than the slope of line $B$, which implies that the cross-sectional area of $A$ is greater than that of $B$ $(A_A > A_B)$.Therefore, statement $A$ is true and statement $D$ is true.

Two wires $A$ and $B$ of the same length are made of the same material. The load $(F)$ vs. elongation $(x)$ graph for these two wires is shown in the figure. Which of the following statement$(s)$ is/are true?

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