An aluminum rod (Young's modulus $Y = 7 \times 10^9 \, N/m^2$) has a breaking strain of $0.2\%$. The minimum cross-sectional area of the rod required to support a load of $10^4 \, N$ is:

  • A
    $1 \times 10^{-2} \, m^2$
  • B
    $1.4 \times 10^{-3} \, m^2$
  • C
    $3.5 \times 10^{-3} \, m^2$
  • D
    $7.1 \times 10^{-4} \, m^2$

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