Two wires of same metal have the same length but their cross-sections are in the ratio $3:1$. They are joined in series. The resistance of the thicker wire is $10\,\Omega$. The total resistance of the combination will be ............. $\Omega$.

  • A
    $40$
  • B
    $\frac{40}{3}$
  • C
    $\frac{5}{2}$
  • D
    $100$

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