The unit for the radioactive decay constant i | vedclass

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Question

(A) The rate of radioactive decay is given by the equation: $-\frac{dN}{dt} = \lambda N$,where $\lambda$ is the decay constant.Rearranging for $\lambd

Vedclass · Accepted Answer

$Time^{-1}$

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(A) The rate of radioactive decay is given by the equation: $-\frac{dN}{dt} = \lambda N$,where $\lambda$ is the decay constant.Rearranging for $\lambda$,we get $\lambda = -\frac{dN/dt}{N}$.Since $dN/dt$ represents the number of disintegrations per unit time and $N$ is the number of nuclei,the unit of $\lambda$ is $	ext{time}^{-1}$ (e.g.,$s^{-1}$,$min^{-1}$,or $year^{-1}$).Therefore,the correct option is $A$.

The unit for the radioactive decay constant is:

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