Use the product $\left[\begin{array}{lll}1 & -1 & 2 \\ 0 & 2 & -3 \\ 3 & -2 & 4\end{array}\right]\left[\begin{array}{lll}-2 & 0 & 1 \\ 9 & 2 & -3 \\ 6 & 1 & -2\end{array}\right]$ to solve the system of equations:
$x-y+2z=1$
$2y-3z=1$
$3x-2y+4z=2$

  • A
    $x=0, y=5, z=3$
  • B
    $x=1, y=2, z=1$
  • C
    $x=2, y=1, z=0$
  • D
    $x=3, y=0, z=5$

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