The value of sec ^{2} theta - frac{sin ^{2} t | vedclass

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Question

(A) Given expression: $\sec ^{2} 	heta - \frac{\sin ^{2} 	heta - 2 \sin ^{4} 	heta}{2 \cos ^{4} 	heta - \cos ^{2} 	heta}$Factor out $\sin^2 	het

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$1$

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(A) Given expression: $\sec ^{2} 	heta - \frac{\sin ^{2} 	heta - 2 \sin ^{4} 	heta}{2 \cos ^{4} 	heta - \cos ^{2} 	heta}$Factor out $\sin^2 	heta$ from the numerator and $\cos^2 	heta$ from the denominator:$= \sec ^{2} 	heta - \frac{\sin ^{2} 	heta (1 - 2 \sin ^{2} 	heta)}{\cos ^{2} 	heta (2 \cos ^{2} 	heta - 1)}$Use the identity $\sin^2 	heta = 1 - \cos^2 	heta$ in the numerator:$= \sec ^{2} 	heta - \frac{\sin ^{2} 	heta [1 - 2(1 - \cos ^{2} 	heta)]}{\cos ^{2} 	heta (2 \cos ^{2} 	heta - 1)}$Simplify the expression inside the bracket:$= \sec ^{2} 	heta - \frac{\sin ^{2} 	heta (1 - 2 + 2 \cos ^{2} 	heta)}{\cos ^{2} 	heta (2 \cos ^{2} 	heta - 1)}$$= \sec ^{2} 	heta - \frac{\sin ^{2} 	heta (2 \cos ^{2} 	heta - 1)}{\cos ^{2} 	heta (2 \cos ^{2} 	heta - 1)}$Cancel the common term $(2 \cos^2 	heta - 1)$:$= \sec ^{2} 	heta - 	an ^{2} 	heta$Using the identity $\sec^2 	heta - 	an^2 	heta = 1$,the final value is $1$.

The value of $\sec ^{2} \theta - \frac{\sin ^{2} \theta - 2 \sin ^{4} \theta}{2 \cos ^{4} \theta - \cos ^{2} \theta}$ is

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