Verify whether the given value of $x$ is a solution of the quadratic equation or not: $(x-2)(x+3)+1=0$; $x=2$.
- AYes,it is a solution.
- BNo,it is not a solution.
- CIt is a root of the equation.
- DThe equation is not defined at $x=2$.
Explore More
Similar Questions
Check whether the following is a quadratic equation:
$(x-2)^{2}+1=2x-3$
$(x-2)^{2}+1=2x-3$
Easy
View SolutionIf $\frac{1}{2}$ is a root of the equation $x^{2}+kx-\frac{5}{4}=0$,then the value of $k$ is
Easy
View SolutionFind the roots of the quadratic equation using the quadratic formula:
$x^{2}+2 \sqrt{2} x-6=0$
$x^{2}+2 \sqrt{2} x-6=0$
Easy
View SolutionFind the roots of the equation $5x^{2}-6x-2=0$ by the method of completing the square.
Difficult
View SolutionWhich of the following is not a quadratic equation?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo