Verify whether the following are zeroes of the polynomial indicated against them:
$p(x) = x^{2} - 1, x = 1, -1$
$p(x) = x^{2} - 1, x = 1, -1$
(A) To verify if $x = 1$ and $x = -1$ are zeroes of the polynomial $p(x) = x^{2} - 1$,we evaluate the polynomial at these values.
For $x = 1$:
$p(1) = (1)^{2} - 1 = 1 - 1 = 0$
For $x = -1$:
$p(-1) = (-1)^{2} - 1 = 1 - 1 = 0$
Since $p(1) = 0$ and $p(-1) = 0$,both $x = 1$ and $x = -1$ are zeroes of the given polynomial $p(x) = x^{2} - 1$.
For $x = 1$:
$p(1) = (1)^{2} - 1 = 1 - 1 = 0$
For $x = -1$:
$p(-1) = (-1)^{2} - 1 = 1 - 1 = 0$
Since $p(1) = 0$ and $p(-1) = 0$,both $x = 1$ and $x = -1$ are zeroes of the given polynomial $p(x) = x^{2} - 1$.
Explore More
Similar Questions
Verify whether the following is a zero of the polynomial indicated against it:
$p(x) = 5x - \pi, \, x = \frac{4}{5}$
$p(x) = 5x - \pi, \, x = \frac{4}{5}$
Easy
View SolutionFor $p(x) = x^{3} + 9x^{2} + 26x + 24$,find the value of $p(-2)$.
Easy
View SolutionState whether the following statement is True or False. Justify your answer.
$A$ polynomial cannot have more than one zero.
$A$ polynomial cannot have more than one zero.
Easy
View SolutionFind the zeroes of the polynomial in each of the following:
$q(x) = 2x - 7$
$q(x) = 2x - 7$
Easy
View SolutionVerify whether the following are zeroes of the polynomial indicated against them:
$p(x) = 3x^2 - 1, x = -\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$
$p(x) = 3x^2 - 1, x = -\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo