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(C) Given: Diameter $D = 1.5 \ cm = 1.5 	imes 10^{-2} \ m$,Flow rate $Q = 7.5 	imes 10^{-5} \ m^3 \ s^{-1}$,Viscosity $\eta = 10^{-3} \ Pa \cdot s$,

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Turbulent with Reynolds number greater than $6000$

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(C) Given: Diameter $D = 1.5 \ cm = 1.5 	imes 10^{-2} \ m$,Flow rate $Q = 7.5 	imes 10^{-5} \ m^3 \ s^{-1}$,Viscosity $\eta = 10^{-3} \ Pa \cdot s$,Density of water $ho = 10^3 \ kg \cdot m^{-3}$.Flow rate $Q = A \cdot v = \frac{\pi}{4} D^2 v$,so velocity $v = \frac{4Q}{\pi D^2}$.Reynolds number $R_e = \frac{ho v D}{\eta} = \frac{ho (\frac{4Q}{\pi D^2}) D}{\eta} = \frac{4 ho Q}{\pi \eta D}$.Substituting the values: $R_e = \frac{4 	imes 10^3 	imes 7.5 	imes 10^{-5}}{3.14 	imes 10^{-3} 	imes 1.5 	imes 10^{-2}}$.$R_e = \frac{0.3}{4.71 	imes 10^{-5}} \approx 6369.4$.Since $R_e > 4000$,the flow is turbulent. Among the given options,the flow is turbulent with a Reynolds number greater than $6000$.

Water flows from a tap of diameter $1.5 \ cm$ with a flow rate of $7.5 \times 10^{-5} \ m^3 \ s^{-1}$. The coefficient of viscosity of water is $10^{-3} \ Pa \cdot s$. The flow is:

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