Water is flowing at the rate of 15, km/h thro | vedclass

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(D) Given: Length of the pond $= 50\, m$,Width of the pond $= 44\, m$.Required rise in water level $= 21\, cm = 0.21\, m$.Volume of water required in

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$2$

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(D) Given: Length of the pond $= 50\, m$,Width of the pond $= 44\, m$.Required rise in water level $= 21\, cm = 0.21\, m$.Volume of water required in the pond $= 50 	imes 44 	imes 0.21 = 462\, m^3$.Radius of the pipe $(r) = \frac{14}{2} = 7\, cm = 0.07\, m$.Speed of water $= 15\, km/h = 15000\, m/h$.Volume of water flowing through the pipe in $1\, h = \pi r^2 	imes 	ext{speed} = \frac{22}{7} 	imes (0.07)^2 	imes 15000$.$= \frac{22}{7} 	imes 0.0049 	imes 15000 = 22 	imes 0.0007 	imes 15000 = 231\, m^3$.Time required to fill $462\, m^3$ of water $= \frac{	ext{Total volume required}}{	ext{Volume flow per hour}} = \frac{462}{231} = 2\, h$.Thus,the required time is $2\, h$.

Water is flowing at the rate of $15\, km/h$ through a pipe of diameter $14\, cm$ into a cuboidal pond which is $50\, m$ long and $44\, m$ wide. In what time will the level of water in the pond rise by $21\, cm$? (in $h$)

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