Water rises in a vertical capillary tube up to a height of $2.0\ cm$. If the tube is inclined at an angle of $60^o$ with the vertical,then up to what length will the water rise in the tube? (in $cm$)

$A$ glass capillary tube of internal radius $r = 0.25 \, mm$ is immersed in water. The top end of the tube projects $2 \, cm$ above the surface of the water. At what angle does the liquid meet the tube (in $^{\circ}$)? (Surface tension of water $T = 0.07 \, N/m$,density $\rho = 1000 \, kg/m^3$,$g = 9.8 \, m/s^2$)

Radius of a capillary is $2 \times 10^{-3} \,m$. $A$ liquid of weight $6.2 \times 10^{-4} \,N$ may remain in the capillary. Then the surface tension of the liquid will be $:-$

$A$ liquid rises to a height of $2.4 \ cm$ in a glass capillary $P$. Another glass capillary $Q$ having a diameter $80\%$ of capillary $P$ is immersed in the same liquid. The rise of liquid in capillary $Q$ is (in $cm$)

$A$ capillary tube of radius $R$ is dipped in water,and water rises to a height $H$. The mass of water in the capillary tube is $M$. If a capillary tube of half the radius is dipped in water,what will be the mass of the water in the capillary tube?

Two capillary tubes of different diameters are dipped in water. The rise of water is