Water rises to a height of $3 \,cm$ in a capillary tube. If the cross-sectional area of the capillary tube is reduced to $1/9$th of its initial area, then the water will rise to a height of: (in $\,cm$)

  • A
    $9$
  • B
    $6$
  • C
    $7$
  • D
    $8$

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