$A$ wave is associated with matter:

What should be the order of arrangement of de-Broglie wavelength of an electron $(\lambda_{e})$,an $\alpha$-particle $(\lambda_{\alpha})$,and a proton $(\lambda_{p})$,given that all have the same kinetic energy?

If the kinetic energy of an electron and a proton are equal,find the ratio of their associated de Broglie wavelengths.

$A$ photon and an electron have equal energy $E$. The ratio $\lambda_{\text{photon}} / \lambda_{\text{electron}}$ is proportional to:

What voltage should be applied to an electron microscope to produce electrons with a wavelength of $\lambda = 1.0 \ \mathring{A}$ (in $V$)?

Find the de-Broglie wavelength of an electron with kinetic energy of $ 120 eV $. (in $pm$)